Chemistry, asked by afladell, 8 months ago

A butane lighter is advertised as being 95% efficient, meaning that 95% of the butane it uses is combusted completely according to the chemical formula below. 2 C4H10(g) + 13 O2(g) → 8 CO2(g) + 10 H2O(l) If this butane lighter uses 15.0 grams of butane, how many grams of carbon dioxide does it produce at 95% efficiency?

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Answered by sagayrajsagaya
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Answer:

2 C4H10(g) + 13 O2(g) → 8 CO2(g) + 10 H2O(l) If this butane lighter uses 15.0 grams of butane, how many

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