Question

a buulet is fired vertically upward with an acceleration of 50m/s square it vover a distance h1 diuringthe frist second and a distance h2 durimg the last 3 second of its upward motion if g.equal to 10m/s h1 and h2 will be relate as​

Answer 1

Explanation:

this is the correct answer for your question

Answer 2

Answer:

using equation of motion :s=ut+

2

at

2

distance traveled in first second:

h

1

=45m

t

a

=

g

u

,where t

a

is time of ascent

t

a

=5s

so at t=2s last 3 sec of upward motion starts

height at t=2s is :

h=50×2−

2

10×4

h=80m

H

max

=

2g

u

2

Hmax=125m

distance traveled in last 3 sec h

2

=H−h

h

2

=125−80

h

2

=45m

therefore h

1

=h

2