Question

a buys 18 comics and decides to divide them among his children in the ratio of their ages.Their ages 9 6 and 3 years .Haw many comics will each child get​

Answer 1

Answer:

Let the ratio of comics be 'x'

9x+6x+3x= 18

18x=18

x=18/18

x=1

so, 9*1=9, 6*1=6,3*1=3

Therefore first child got 9 books, second child got 6 books and third child got 3 books.

Answer 2

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✬ Comics = 9 , 6 & 3 ✬

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⭐GIVEN⭐

Total number of comics he bought is 18.

Ages of his children are 9 years , 6 years and 3 years.

To Find:

How many comics each of them will get ?

Solution: Let x be the common in given ratios of children ages. Therefore

First child = 9x comics

Second child = 6x comics

Third child = 3x comics

∴ Total ratio = 9x + 6x + 3x

➙ Total ratio = 18x

Now , let's find the value of x.

$\implies{\rm }Total ratio = Total comics$

$\implies{\rm }18x = 18$

$\implies{\rm }x = 18/18$

$\implies{\rm } x = 1$

So the number of comics each will get is

➯ First child = 9x = 9 × 1 = 9 comics

➯ Second child = 6x = 6 × 1 = 6 comics

➯ Third child = 3x = 3 × 1 = 3 comics

Hence, they will get 9 , 6 and 3 comics respectively.

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