A buys a radio at 3/4th of its market price and sells it at 20/: more than the marked price .What is A's gain percent?
Answers
Step-by-step explanation:
the radio of the market = 3/4th
price of it's market = 20/:
the paresent of the market
=3/4maltiplaed20$ answer is 15
Step-by-step explanation:
Given :-
A buys a radio at 3/4th of its market price and sells it at 20% more than the marked price .
To find :-
What is A's gain percent?
Solution:-
Let the marked price of the radio be Rs. X
Cost Price of the radio = 3/4th of the MP
=> Cost Price = (3/4)×X
=> Cost Price = Rs. 3X/4
Selling Price of the radio = 20% more than the Marked Price
=> Selling Price = 20% of MP + MP
=> Selling Price = 20% ×X + X
=> Selling Price = (20/100)×X + X
=> Selling Price = (1/5)×X + X
=> Selling Price = (X/5)+X
=> Selling Price = (X+5X)/5
=> Selling Price = Rs. 6X/5
We have ,
SP = Rs. 6X/5 and CP = Rs. 3X/4
SP > CP
Gain = SP - CP
=> Gain = (6X/5) - (3X/4)
LCM of 4 and 5 = 20
=> Gain = (24X-15X)/20
=> Gain = Rs. 9X/20
We know that
Gain% = ( Gain /Cost Price) × 100
=> Gain% = [(9X/20)/(3X/4)]×100
=> Gain% = [(9X/20)×(4/3X)]×100
=> Gain % = [(9X×4)/(20×3X)]×100
=> Gain% = (36X/60X)×100
=> Gain% = (3/5)×100
=> Gain% = (3×100)/5
=> Gain% = 300/5
=> Gain % = 60%
Answer:-
Gain Percentage of A for the given problem is 60%
Used formulae:-
→ Gain = Selling Price - Cost Price
→ Gain% = ( Gain /Cost Price) × 100