A buys a radio at3/4th of its marked price and sells it at 20% more than the marked price. What is A's gain percent?
Answers
Step-by-step explanation:
- here A buys 3/4th value of Market price =25percentage. 2.he sells more than 20percentage market price do he gains =45 percentage. 3.total gain =70 percentage
Step-by-step explanation:
Given :-
A buys a radio at 3/4th of its marked price and sells it at 20% more than the marked price.
To find :-
What is A's gain percent?
Solution :-
Let the Marked Price of the radio be Rs. X
Cost Price of the radio
= 3/4th of the Marked Price
= (3/4) of X
= (3/4)×X
=(3×X)/4
= 3X/4
Cost Price of the radio = Rs. 3X/4
and
Selling Price of the radio
= 20% more than the marked price
= 20% more than X
= X+20% of X
= X+(20/100)×X
= X+(1/5)×X
= X+(X/5)
= (5X+X)/5
= 6X/5
Selling Price of the radio = Rs. 6X/5
We have ,
CP = Rs. 3X/4 and SP = Rs. 6X/5
SP > CP
=> Gain occurs
We know that
Gain = Selling Price- Cost Price
=> Gain = (6X/5)-(3X/4)
LCM of 5 and 4 = 20
=> Gain = (24X-15X)/20
=> Gain = 9X/20
Gain = Rs. 9X/20
We know that
Gain % = (Gain/CP )×100
=> G% = [(9X/20)/(3X/4)]×100
=> G% = [(9X/20)×(4/3X)]×100
=> G% = [(9X×4)/(20×3X)]×100
=> G% = (36X/60X)×100
=> G% = (3/5)×100
=> G% = (3×100)/5
=> G% = 300/5
=> G% = 60%
Therefore, gain % of A = 60%
Answer:-
The gain percentage of A on the radio is 60%
Used formulae:-
→ Gain = Selling Price- Cost Price
→ Gain % = (Gain/CP )×100