Question

(a+bw+cw2) /(c+aw+bw2)
= w2​

Answer 1

Hey mate here is ur ans

Here, the denominator expression of LHS should be= aw + bw² + c , then only the RHS = w²

LHS = (a + bw + cw² ) / (aw + bw² + c)

= w ( a + bw + cw² ) / w( aw + bw² + c)

=( aw + bw² + cw^3 ) / w ( aw + bw² + c ) . . . . .(1)

Now, since w = cube root of 1

=> w^3 = 1

By putting up this value in eq(1)

= (aw + bw² + c ) / w ( aw +bw² + c)

= 1/w

= w^3 / w ( since w^3 = 1)

= w² = RHS

=> LHS = RHS



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