Question

a/bx - b/ax = a²- b²
solve for x​

Answer 1

GiveN :

• a/bx - b/ax = a² - b²

To FinD :

• Value of x

SolutioN :

⇒a/bx - b/ax = a²- b²

Here 1/x is common in both the sides, so take 1/x as common from both of the sides.

⇒ 1/x (a/b - b/a) = a²- b²

Now take LCM of (a/b - b/a)

⇒ 1/x (a²- b²/ba) = a²- b²

Now, (a² - b²) is also commons, So cancel out (a² - b²) from both of the sides.

⇒1/x = ab

⇒x = 1/ab

• So, value of x is 1/ab

Answer 2

value of x = $\large\sf\frac{1}{ab}$

$\Large\sf\frac{a}{bx}\:-\: \frac{b}{ax}$ = a² - b²

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$\Large\sf\frac{1}{x}$ are common

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$\Large\sf\frac{1}{x}$ ($\large\sf\frac{a}{bx} -\frac{b}{ax}$) = a² - b²

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$\Large\sf\frac{1}{x}$ ($\large\sf\frac{a^2 - b^2}{ba}$) = a² - b²

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a² - b² is cancel

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so,

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$\Large\sf\frac{1}{x}$ = ab

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x = $\LARGE\sf\frac{1}{ab}$