a by walking with a speed of 30km/hr reaches his school 40 min late next time he increases his speed 10km/hr but stell he is late by 10min find the distance of his school from his house
Answers
Answer:
he is the first to make short intro of wasseypur and unless he has the ability of a bad way for the rest he plays the same thing he plays in a situation like that
Step-by-step explanation:
the company is a member and your company has been in the process for the last year or two and unless you are
Answer:
Step-by-step explanation:
let the distance of school from house = x and time = t
CASE 1,
speed of boy = 10 km/hr
he is late by = 15 mins = 15/60 hr
=> x/10 = t - 15/60
=> (x/10) + (15/60) = t. - - - (1)
CASE 2
speed increased by = 2 km/hr
new speed = 10 + 2 = 12km/hr
he is late by = 5 mins = 5/60 hr
=> x/12 = t - (5/60)
=> (x/12) + (5/60) = t. - - -(2)
equating (1) and (2)
x/12. + 5/60. = x/10 + 15/60
=> x/12 - x/10. = (15-5)/60
=> x/60 = 10/60
=> x = 10