a
C
b
a2b2 c2
a3 b3 c3=
abc(a - b)(b-c)(C-a)
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Answer:
13. a3+b3+c3–3abc≡(a+b+c)(a2+b2+c2–ab– bc–ca). 14. (a+b)2=(a–b)2+4ab. 15. ... Factorise using the Identity a2–b2 = (a+b)(a–b) a)x2–9.
Step-by-step explanation:
looks pretty hard but I will try my best hope it will help you
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