Question

a=c^z,b=a^x and c=b^y, prove xyz =1
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Answer 1

To prove: xyz=1

prove: a= c^x -----1

b= a^x ------2

b^1/x=a ------3

c= b^y

Equating 1 and 2 we get,

c^z= b^1/x

(b^y)^z= b^ 1/x (putting c= b^y)

b^yz= b^1/x

yz= 1/x ( removing same bases)

xyz=1 (proved)

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