A cab service provider charges a fixed amount for the first 10 kilometres and charges a certain amount for every additional kilometre. Jenny travels 50 km and her cab fare amounts to ₹975. Selina’s cab fare amounts to ₹675 when she travels 35 km. How much does the cab charge for the first 10 km?
Answers
Answer:
Let the fixed amount be 'x Rs', for 10km.
Let the certain amount he charges for every additional kilometre be y Rs.
Jenny travels 50km.
We can split 50km as 10km and 40km.
Thus, the equation we form:
10x+40y=₹975.................(1)
Selina travels 35km.
We can split 35km as 10km and 25km.
Thus, the equation we form:
10x+25y=₹675............(2)
First, subtract (1) and (2). You will get:
15x=300
x=300/15
x=20₹.
The cab charges 20₹ for the first 10 km.
Well, seems like you are preparing for exams... Here's a question for you, try to solve it:
One says, “Give me a hundred, friend! I shall then become twice as rich as you”. The other replies, “If you give me ten, I shall be six times as rich as you”. Tell me what is the amount of their (respective) capital? [From the Bijaganita of Bhaskara II]
[Hint : x + 100 = 2(y – 100), y + 10 = 6(x – 10)].
HOPE THIS HELPS :D