Question

A cable car initially moving with a velocity of 10 ms-1 accelerates for 5s at a rate of 2ms 2. Find the final velocity of the cable car.​

Answer 1

Answer

Initial Velocity (u) = 10 m/sec

Acceleration (a) = 5 m/sec

2

Distance (s) = 30 m

Final velocity (v) = ??

Using Newton's Third law of Motion,

v

2

=u

2

+2as

v

2

=10

2

+2×5×30

v

2

=100+300

v

2

=400

v =

400

v = 20 m/sec

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