Question

A cable is hung between two towers that are 200 feetsapart. The cable takes the shape of a catenary whose equation is
$y=75(e^{\frac{x}{150} }+e^{-\frac{x}{150} })$
Find the arc length of the cable between the two towers.

Answer 1

Answer:

Did you mean: A cable is hung between two towers that are 200 feet apart. The cable takes the shape of a catenary whose equation is y=75(e^{\frac{x}{150} }+e^{-\frac{x}{150} })y=75(e 150 x +e − 150 x ) Find the arc length of the cable between the two towers