a cable is pulling a box with mass 300kg on a horizontal plane .the cable acts 60° on the direction of movement of the box.if the tension in the cable is 1000N and the bos is move for 4.5 m.calculate the work done to move the box.
Answers
Answer:
W = (100 N) * (5 m)* cos(0 degrees) = 500 J
The force and the displacement are given in the problem statement. It is said (or shown or implied) that the force and the displacement are both rightward. Since F and d are in the same direction,the angle is 0 degrees.
Diagram B Answer:
W = (100 N) * (5 m) * cos(30 degrees) = 433 J
The force and the displacement are given in theproblem statement. It is said that the displacement is rightward. It is shown that the force is 30 degrees above the horizontal. Thus, the angle between F and d is 30 degrees.
Diagram C Answer:
W = (147 N) * (5 m) * cos(0 degrees) = 735 J
The displacement is given in the problem statement. The applied force must be 147 N since the 15-kg mass (Fgrav=147 N) is lifted at constant speed. Since F and d are in the same direction, the angle is 0 degrees.
Explanation:
☝️☝️☝️☝️☝️☝️☝️☝️