Question

A cable of resistance 12 carries electric power from a generator producing 250 kw at 10,000v. Calculate (i) the current in the cable, (ii) the power lost in the cable during transmission, and (iii) the p.D. Across the ends of the cable.

Answer 1

Answer:

Given P=250kW=250×1000W and V=10000V

As P=VI

so current in the cable I=VP=10000250×1000=25A