Computer Science, asked by biswakarmamanisha056, 6 hours ago

A cable stores different types of data ? ture or false ​

Answers

Answered by Aaaryaa
0

Answer:

true

cable stores different types of data

Answered by user0172
0

Answer:

False

Explanation:

✭ Density of ethylene glycol = 1.09 g/mL

✭ Volume of water = 375 mL

✭ Concentration (v/v) = 7.5 %

\large\underline{\sf{\blue{To\:Find}}}

ToFind

✭ How many grams of ethylene glycol should be mixed with 375 mL of water to make a 7.50% (v/v) mixture?

\large\underline{\sf{\gray{Solution}}}

Solution

◈ Let volume of solute (ethylene glycol) be 'v' mL

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Finding volume of the solution,

\small\sf\Rightarrow\: Volume_{(solution)} = Volume_{(solute)} + Volume_{(solvent)}⇒Volume

(solution)

=Volume

(solute)

+Volume

(solvent)

\small\Rightarrow\:\sf Volume_{(solution)} = v + 375⇒Volume

(solution)

=v+375

\small\Rightarrow\:\sf \pink {Volume_{(solution)} = (v + 375)\:mL}⇒Volume

(solution)

=(v+375)mL

Now,

➳ \small\sf Concentration\:(v/v) = \dfrac{Volume_{(solute)}}{Volume_{(solution)}}\:\times\:100Concentration(v/v)=

Volume

(solution)

Volume

(solute)

×100

➳ \small\sf 7.5 = \dfrac{v}{v + 375}\:\times\:1007.5=

v+375

v

×100

➳ \small\sf 7.5 = \dfrac{100v}{v + 375}7.5=

v+375

100v

➳ \small\sf 7.5(v + 375) = 100v7.5(v+375)=100v

➳ \small\sf 7.5v + 2812.5 = 100v7.5v+2812.5=100v

➳ \small\sf 2812.5 = 100v - 7.5v2812.5=100v−7.5v

➳ \small\sf 2812.5 = 92.5v2812.5=92.5v

➳ \small\sf v = \dfrac{2812.5}{92.5}v=

92.5

2812.5

➳ \small\sf v = {\cancel{\dfrac{2812.5}{92.5}}}v=

92.5

2812.5

➳ \small\sf\pink{ v = 30.4\:mL}v=30.4mL

We know that,

⪼ \underline{\boxed{\sf{Mass = Volume\:\times\:Density}}}

Mass=Volume×Density

Finding mass of ethylene solution to be mixed,

\small\sf \rightarrow\: Mass_{(ethylene\:glycol)} = Volume_{(ethylene\:glycol)} \:\times\: Density_{(ethylene\:glycol)}→Mass

(ethyleneglycol)

=Volume

(ethyleneglycol)

×Density

(ethyleneglycol)

\small\rightarrow\:\sf Mass_{(ethylene\:glycol)} = 30.4 \:\times\:1.09→Mass

(ethyleneglycol)

=30.4×1.09

\small\rightarrow\:\sf\pink{Mass_{(ethylene\:glycol)} = 33.136\:g}→Mass

(ethyleneglycol)

=33.136g

\small\therefore\:{\underline{\sf{Mass\:of\:ethylene\:glycol\:to\:be\:mixed\:=\:{\textsf{\textbf{33.136\:g}}}}}}∴

Massofethyleneglycoltobemixed=33.136g

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