Math, asked by elona, 8 months ago

A cake is cut into 3 pieces whose weights are in the ratio 2:1:4

It the third piece weighs 360g more than the second, how much did the whole cake weigh?

A. 1.44 kg
B. 1.26 kg
C. 840 g
D. 630 g

( WITH EXPLANATION )​

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Answers

Answered by Jai2708rai
22

Answer:

840g

Step-by-step explanation:

it is given that weight of third peice is more by 360

so

4x=x+360

x = 120

so total weight of cake = 2X + 1X + 4x

(2*120 )+(1*120) +(4*120)=840grams

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Answered by Anonymous
3

Given :

  • A cake is cut into 3 pieces whose weights are in the ratio 2:1:4
  • Third piece weighs 360g more than the second.

To find : The weight of the whole cake.

Solution :

The weight of the whole cake is 840g

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the weight of the total cake)

Let, the weight of three pieces = 2x grams , x grams and 4x grams

(obtained from the ratio 2:1:4)

Weight of second piece = x grams

Weight of third piece = 4x grams

Different between the weight of third piece and second piece = (4x-x) = 3x grams

According to the data mentioned in the question,

3x = 360

x = 360/3

x = 120

So,

  • Weight of first piece = 2x = 2×120 = 240g
  • Weight of second piece = x = 120g
  • Weight of third piece = 4x = 4×120 = 480g

And, Weight of the whole cake = (240+120+480) = 840g

(This will be considered as the final result.)

Hence, the weight of the whole cake is 840g

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