Question

A cake is divided into 18 pieces. if A takes 1/3 of the cake and B takes 1/3 of the rest that are left how many pieces are still left​

Answer 1

Answer:

total pieces =18

A takes =1/3

B takes =1/3

. total taken part =

$\frac{1}{3} + \frac{1}{3}$

$= \frac{2}{3}$

actual piece taken =

$\frac{2}{3} \times 18 = 12$

rest pieces are 18-12=6