Question

a cake was shared by three friends.jacob ate 2\5 of the cake,sandeep ate 3\8 of the cake and hammad ate the rest of the cake.who ate the biggest share of the cake?​

Answer 1

Answer:

Jacob ate the biggest share of the cake...

Step-by-step explanation:

Jacob ate =2/5

Sandeep ate =3/8

find LCM of these numbers..

$\frac{2}{5} \: and \: \frac{3}{8}$

$5 \times 8 = 40$

$\frac{2 \times 8}{40} = \frac{16}{40}$

$\frac{3 \times 5}{40} = \frac{15}{40}$

The balance portion = 40 - (16 + 15 )

= 40 - 31

Hammad ate = 9/40

$\frac{9}{40}$

Therefore Jacob ate the biggest share of the cake...

Answer 2

Let the cake eaten by hammad=x

(2/5)+(3/8)+x=1

(31/40)+x=1

x=1-(31/40)

x=9/40

Cake eaten by jacob=2/5=0.4

Cake eaten by sandeep=3/8=0.375

Cake eaten by Hammad=0.225

Therefore Jacob ate the biggest share of cake.

hope it helps you mark as brainliest please