Question

A calcium chloride solution has a molarity of 1.52M. What volume of
the solution (in mL) would contain 0.500mol of the solute?

Answer 1

Answer:

329 mL

here's the answer and hope this helps you.

Answer 2

Given:

Molarity of Calcium Chloride Solution, 1.52mol L¯¹

Solution:

This statement means that 1.52moles of CaCl₂(solute) is dissolved in 1 Litre of a solution.

,i.e., 1.52mol ≡ 1000mL

On dividing both sides by 1.52 :–

1 mol ≡ 1000/1.52mL

⇒1 mol ≡ 657.9mL

On dividing both sides by 2 :–

⇒0.5mol ≡ 328.95mL

Therefore, approximately 329mL of solution will contain 0.5mol.