Question

A calcium compound X on heating form a white solid Y and gas Z .X also reacts with dilute acid to form a gas Z which turns milky.The white solid Y dissolves in water forming colorless solution which turns universal indicator blue

Answer 1

X - Calcium Carbonate (CaCO3)
Y - Calcium oxide (CaO)
Z - Carbon dioxide (CO2)
The base formed when Y is dissolved in water - Calcium hydroxide (CaOH)

Answer 2

Identification of compound X, Y, and Z

1. A calcium compound X on heating form a white solid Y and gas Z.

• When calcium carbonate is heated, it leads to the formation of two product among which one is solid called calcium oxide whereas the other is gas called carbon dioxide.
• The reaction involved is as follows:

$C a C O_{3} \stackrel{\Delta}{\rightarrow} Ca O+C O_{2}$

• Gas Z is inferred as carbon dioxide because it is the only gas that turns milky.

2. Reaction of X, with dilute such as HCl forms gas Z

• When $CaCO_3$ is treated with dil HCl it leads to the following product

$CaCO_3+HCl \rightarrow CaCl_2+CO_2+H_2O$.

3. The white solid Y dissolves in water forming colorless solution which turns universal indicator blue

• When CaO obtained in the first reaction is dissolved in water it leads to the formation of calcium hydroxide solution. The reaction involved is

$CaO+H_2O\rightarrow Ca(OH)_2$

• This solution turns universal indicator blue as its pH value is 11 and it is a weak base.

• Thus the compounds are identified as:

1. X - Calcium carbonate $(CaCO_3)$
2. Y - Calcium oxide $(CaO)$
3. Z - Carbon dioxide $(CO_2)$

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