Question

A)calculate effective resistance B) calculate total current C)calculate the potential difference across 10 0hm in the above figure​ ( voltage ) 6 Volt​

Answer 1

Answer:

When 8 and 12 are in parallel

and 7.2 is in series with them

Net Resistance

10

7.2

+

12+8

8×12

=

10

72

+

20

96

=

10

72

+

10

48

=

10

120

=12Ω

Total current =

netR

V

=

12

6

=0.5Ω

Voltage across R

1

=iR

1

=0.5×7.2

=3.6

solution

expand

Answer 2

Given :

Two resistors are connected in series combination,

• R₁ = 5 ohms
• R₂ = 10 ohms

Potential difference : 6 volts.

To find :

A) calculate effective resistance

B) calculate total current

C) calculate the potential difference across 10 ohm.

Solution :

we know that,

» The combined resistance of any number of resistance connected in series is equal to the sum of the individual resistances. i.e.,

R = R₁ + R₂

By substituting the values in the formula,

$\dashrightarrow \sf R_{s} = R_{1} + R_{2}$

$\dashrightarrow \sf R_{s} = 5 + 10$

$\dashrightarrow \sf R_{s} = 15 \: ohms$

Thus, the effective resistance is 15 ohms.

Now, using Ohms law that is,

» At constant temperature the current flowing through a conductor is directly proportional to the potential difference across its ends.

Formula : V = RI

where,

• V denotes potential difference
• R denotes resistance
• I denotes current

substituting all the given values in the formula,

$\dashrightarrow \sf V = RI$

$\dashrightarrow \sf6= (15)I$

$\dashrightarrow \sf I = \dfrac{6}{15}$

$\dashrightarrow \sf I = 0.2A$

Thus, the total current is 0.2 A.

Now, using ohms law we can find potential difference across 10 0hm.

$\dashrightarrow \sf V = RI$

$\dashrightarrow \sf V = (10)(0.4)$

$\dashrightarrow \sf V = 4 \: volts$

Thus, the potential difference across 10 0hm is 4 volts.