Question

a) calculate the amount of water (g) produced by the combustion of 16g of methne (b) calculate the number of molecules of ethane [ C6 H6] present in 5 moles of ethane​

Answer 1

Answer:

a) Combustion of methane :

CH

4

+2O

2

⟶CO

2

+2H

2

O

Given weight of methane =16g

Molecular weight of methane =16g

No. of moles of methane in 16g of it =

mol. wt.

given wt.

=

16

16

=1 mole

From the reaction,

Amount of water produced by the combustion of 1 mole of methane = 2 moles

weight of 1 mole of water =18g

⇒ weight of 2 moles of water =2×18=36g

Since, the given weight of methane is 16 g, hence the water produced by the combustion of 16 g of methane is 36 g.

b) 1 mole of (C6H6) contains 6.023 × 1023 molecules of ethane(because 1mole = 6.022 x 1023)

∴ Number of molecules in 6 moles of C6H6

= 6 × 6.023 × 1023 = 36.138 × 1023

Thankyou friends