Question

(a) Calculate the energy of 1 mole of nitrogen gas at 27oc. Compare the energy of 1 mole of hydrogen gas at this temperature with the corresponding value of nitrogen gas (Given-: Boltzmann Constant (k=1.38 x 10-23 jk-1)

Answer 1

The ideal gas equation relating pressure (P), volume (V), and absolute temperature (T) is given as: PV = nRT

Where, R is the universal gas constant = 8.314 J mol–1 K–1

n = Number of moles = 1

T = Standard temperature = 273 K

P = Standard pressure = 1 atm = 1.013 × 105 Nm–2

= 0.0224 m3

= 22.4 litres

Hence, the molar volume of a gas at STP is 22.4 litres

Answer 2

Answer:

◆ KE of ideal gas=3/2nRT

◆ n=1 mole

◆ R=8.314 jk^-1mol^-1

◆ T=300k

◆hence KE=3/2*1*8.314*300=3741.3 J

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