Question

a) Calculate the height of a water column which will
exert on its base the same pressure as the 70 cm
column of mercury. Density of mercury is 13.6 g cm3 find the change if the crosssection of the water is made wider​

Answer 1

Answer:

=> Pressure exerted by mercury = 952 g. => Pressure exerted by water = h g. => h = 952 cm. Therefore, the height of water column which will exert on its base the same pressure as the 70 cm column of mercury is 952 cm.

Answer 2

Step-by-step explanation:

Pressure will remain same for both the liquids.

Hence, Pressure = ρ×g×h

ρ = density of the liquid

g = acceleration due to gravity

h = height of the column

⟹ρ

mercury

×g×h

mercury

=ρ

water

×g×h

water

⟹ρ

mercury

×h

mercury

=ρ

water

×h

water

Given, ρ

mercury

=13.6 h

mercury

=70

ρ

water

=1 h

water

=?

Hence,

h

water

=

13.6×70/1

h

water

=952cm