Question

(A) Calculate the mass and volume of oxygen required at STP to convert
2.4kg of graphite into carbon dioxide​

Answer 1

According to the reaction Moles of graphite = moles of oxygen required.

So X = 54.54 X 32 = 1745.45g = 1.75Kg.

And Volume = 54.54 X 22.4 ltrs = 1221.696 L

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Answer 2

Explanation:

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