Question

a) Calculate the maximum efficieny of an engine operating between 220C and 125C.​

Answer 1

Answer:

maximum efficiency of the engine is 19.27%

Explanation:

Mathematically,

Efficiency, η = (T2 – T1) / T2

T2 = 220 C = 220 + 273 = 493 K

T1 = 125 C = 125 + 273 = 398 K

Therefore,

η = (T2 – T1) / T2

= (493 – 398) / 493

= .1927 = 19.27%

Hence maximum efficiency of the engine is 19.27%

Answer 2

Answer:

Maximum efficiency of an engine.

For engine we have,

A = 220 + 273 = 493K .

B = 125 + 273 = 398K .

n = A - B / A

n = 493 - 398 / 398 .

n = 95 / 398 .

n = 23.869%

Therefore the maximum efficiency of an engine operating between to 220C and 125C is 23.8 69%