Question

(a) Calculate the momentum of a 2000 kg elephant charging a hunter at a speed of 7.50m/s. (b) Compare the elephant's momentum with the momentum of a 0.0400 kg tranquilizer dart fired at a speed of 600 m/s. (c) what is the momentum of the 90 kg hunter running at 7.40 m/s after missing the elephant?​

Answer 1

Answer:

Explanation:

Here ;

a ) Solution :

     mass of elephant(m1) = 2000 kg

    speed of the hunter (v1)=  7.50 m/s

Therefore ,  Momentum of the elephant  (ρ1) =  m * v =m1*v1 =  2000 * 7.50 =  15000 $kgms^{-1}$

b) Solution :

 The momentum  of the elephant is (ρ1) = 15000 $kgms^{-1}$

Now, the momentum of tranquilizer (ρ2) ;

mass of the tranquilizer ( m2) = 0.0400 kg

Speed (v2) = 600 m/s

The momentum  of the   tranquilizer(ρ2)  = m2 * v2 = 0.0400 * 600

                                                                      = 24 $kgms^{-1}$

Then;

ρ1 / ρ2  = 15000 / 24 = 625

Therefore, ρ1  = 625 ρ2

Hence , the momentum of the elephant is625 times  than the momentum of the  tranquilizer.

c) Solution :

mass of the hunter ( m3 ) = 90 kg

Speed ( v3) = 7.40 m/s

Therefore, the momentum  of the hunter = m3 * v3 = 90 * 7.40 = 666 $kgms^{-1}$

 

Answer 2

Answer:

given

M=2000kg

V=7.50m/s

P=mw

=2000kg(7.50 m/s)

=15.000 kg m/s

Explanation: