A. Calculate the pH of 0.2M of Ca(OH)2 assuming that Ca(OH)2 is completely dissociated in solution.
B. If the solution in (a) above is saturated calculate the solubility of Ca(OH)2 in g/dm^3
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Explanation:
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Let S M be the solubility of Ca(OH)2 in pure water.
SCa(OH)2⇌SCa2+2SOH−
Ksp=[Ca2+][OH−]
Substitute values in the above expression.
4.42×10−5=S(2S)2 or S=0.0223M
500 ml of solution contains 0.01115 moles of calcium ions.
The molarity of NaOH solution is 0.4 M. When it is mixed with equal volume of calcium hydroxide solution, its molarity is reduced to half, i.e., 0.2M.
[OH−]=0.2M
[Ca2+]=[OH−]2Ksp=(0.2)24.42×10−5=0.001105M.
The number of moles of calcium ion precipitated =0.01115−0.001105=0.010045.
The number of milimoles of calcium hydroxide precipitated =0.010045×74×1000=743 mg.
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