Question

a. calculate the potential at point P due to charge of 6×10-7c located 12cm away. b. obtain the work done in a bringing a charge of 3×10-9c from infinity to the point p. does the answer depend on the path along which the charge is brought ?​

Answer 1

this is how we have to solve but put your value and do it

Answer 2

Answer:

The potential at a point P is due to a charge of 6 * 10^-7 C which is at a distance of 12cm from the charge is $4.5*10^{4}J/C$, the work  required in bringing a charge of 3 * 10^-9 C from infinity to P is $13.5*10^{-5}J$

Explanation:

• The potential due to a charge (q) at a distance (r) from it is given by the formula   $V=Kq/r$

From the question, we have

the charge $q=6*10^{-7}C$

distance to the point P $r=12cm=0.12m$

⇒ the potential at that point $V=\frac{9*10^{9}*6*10^{-7} }{0.12} =4.5*10^{4} J/C$

• The work done to  bring a charge from infinity is nothing but the product of potential at that point and charge $W=Vq$

we have given that

the charge is $q=3*10^{-9}C$

potential at that point is calculated as $V=4.5*10^{4} J/C$

⇒ work done $W=4.5*10^{4} *3*10^{-9} =13.5*10^{-5}J$

The work done do not depend on the path followed