Question

a) Calculate the ratio in which the line joining A (-4,2) and B(3,6) is divided by point

P(x, 3). Also find ‘x’ is​

Answer 1

Answer:

let (x,3) divides (-4,2) (3,6) in ratio m:n

3=(6m+2n)/(m+n)

3m+3n=6m+2n

3m=n

m:n=1:3

x=(3-12)/(1+3)

x= -9/4

Answer 2

Answer:

X = -9/4 ; ration = 1:3

Step-by-step explanation:

let the ration be = m:n

given : A(-4,2) ; B(3,6) ; P(x,3)

x1 = -4 ; y1= 2 ; x2=3 ; y2=6;

according to the section formula :

P( )= (mx2+nx1/m + n ; my2+ny1/ m + n);

P(x,3)= (3m-4n/m + n ; 6m+2n/m + n);

now equating the corresponding values :

x = 3m - 4n / m + n ; ( i )

3 = 6m + 2n / m + n ;

3m + 3n = 6m + 2n ;

therefore ;

1n = 3m ;

1:3 = m:n;

now substitute the values of m and n in e q n ( i )

x = -9/4;

hope it helps