Question

(a) Calculate the total resistance across AB. (b) If a cell of e.m.f 2.4 V with negligible internal resistance is connected across AB then calculate the current drawn from the cell

Answer 1

Answer:

R=4Ω, I=0.6A

Explanation:

Answer 2

Given: the resistances or 3 resistors are 3Ω, 5Ω, 8Ω. The e.m.f of cell is 2.4V.

To find: (a) total resistance across AB.

             (b) current

Step-by-step explanation:

Step 1 of 2

Resistors  3Ω, 5Ω are in series. So, the resistance will be:

$R_{S} =R_{1} +R_{2} \\R_{S} =3+5\\R_{S} =8ohm$

The total resistance across AB is:

$\frac{1}{R_{T} } =\frac{1}{R_{1} } +\frac{1}{R_{2} } \\\frac{1}{R_{T} } =\frac{1}{8 } +\frac{1}{8 } \\\frac{1}{R_{T} } =\frac{2}{8} \\R_{T} =4ohm$

Step 2 of 2

$V=IR\\I=\frac{V}{R} \\I=\frac{2.4}{4} \\I=0.6A$

(a) The total resistance is 4 ohm.

(b) The current drawn is 0.6A.