a calf is tied with a rope of length 6m at the corner of square grassy lawn of side 20 m. if the length of the rope is increased by 5.5 m, find the increase in area of the grassy lawn in which the calf can graze.
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Answer:
75.56 m^2
Step-by-step explanation:
Earlier Area grazed by calf = (90/360) * pie * (6)^2
= (1/4) * 3.14 * 36
= 9 * 3.14
= 28.26 m^2
Later Area grazed by Calf = (90/360) * pie * (6+5.5)^2
= (1/4) * 3.14 * 132.25
= 103.82 m^2
Increase in grazed area = 103.82 - 28.26 = 75.56 m^2
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