A calf is tied with a rope of length 6m at the corner of a square grassy lawn of side 20m. If the length of the rope is increased by 5.5m, find the increase in area of the grassy lawn in which the calf can graze
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area of grass land that calf can gaze= πr^2/4
(22/7×6)/4
After increasing length of rope
Area of land that can be gazed by calf =22/7 ×11.5) /4
Difference = 22/28( 11.5-6)
=============22/28 ×5.5
============121/28
percentage of increase ={ (121/28)/(132/28)}×100
====================121/132 ×100
====================91.67%
(22/7×6)/4
After increasing length of rope
Area of land that can be gazed by calf =22/7 ×11.5) /4
Difference = 22/28( 11.5-6)
=============22/28 ×5.5
============121/28
percentage of increase ={ (121/28)/(132/28)}×100
====================121/132 ×100
====================91.67%
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