Question

A calorimeter of mass 100 g and specific heat 0.1 CGS units contains 50 g of water
at 25°C. When some ice is added, the resultant temperature is 20°C. find the mass
of ice added.​

Answer 1

1) Net Heat Change in this Process = 0

2) ice will be converted to water, then all will come at a equilibrium. Temperature.

Units are in SI system.

Steps:

1) Given,

Mass of Caloriemeter, m=100g=0.1kg

Specific Heat of Caloriemeter, S(C)=0.1units

Mass of liquid, m.=0.25kg

Specific Heat of Liquid, s(L)=0.4units

Mass of Ice, =0.01kg

Latent heat of fusion of Ice, L(f)=80units

Specific heat of water, S(w)=1units.

2) Heat due to fusion =mL

Heat due to change in T=ms∗del(T)

Let the final Equilibrium Temperature be T. Celsius.

Q(net)=Q(1)+Q(2)+Q(3)+Q(4)0=0.1∗0.1(T−30)+0.25∗0.4(T−30)+0.01∗80+1∗0.01(T−0)

Multiply by 100 on both sides,

0=T−30+10(T−30)+80+T

12T=250

T=20.83°C

Therefore, Final Temperature of mixture =20.83°C

Answer 2

Answer:

3 gram

Explanation:

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