A calorimeter of mass 25.5g has specific heat capacity of 0.42Jg-1 0C-1. Calculate its heat capacity.
Answers
Explanation:
Heat energy given by metal piece =m⋅c⋅
ΔT 1
= 20×0.3×
(100−22)
= 468J
Heat energy gained by water = mw×cw ×
ΔT 2
= mw ×4.2×
(22−20)
= mw×8.4J
Heat energy gained by calorimeter =mc×
cc×ΔT 2
= 50×0.42×
(22−20)
=42 J
By principle of calorimeter:
Heat lost = Heat gained
Heat energy given by metal = Heat energy gained by water + Heat energy gained by calorimeter
468=mw×8.4+42
mw = 468−42
8.4
=50.7g
Therefore, the mass f water used in the calorimeter is 50.7g.