Question

A calorimeter of mass 50g and specific heat capacity 0.42g/JC contains some mass of water at 20°C.A metal piece of mass 20g at 100°C is dropped into calorimeter. After stiring the final temperature of the mixture is 22°C.Find the mass of water used.
Specific heat capacity of metal piece=0.3J/gC
S.H.C of water=4.2J/gC

Answer 1

Heat energy given by metal piece =  

Heat energy gained by water =

  

Heat energy gained by calorimeter =  

By principle of calorimetry,

           Heat loss = heat gained

Heat energy given by metal = Heat energy gained by water + Heat energy gained by calorimeter



Answer 2

Heat energy given by metal piece =  

Heat energy gained by water =

  

Heat energy gained by calorimeter =  

By principle of calorimetry,

           Heat loss = heat gained

Heat energy given by metal = Heat energy gained by water + Heat energy gained by calorimeter