A calorimeter of negligible thermal capacity contains 150g of water at 40°c .When some pieces of ice are dropped ,ice melts fully and temperature of mixture is 16°c .calculate the mass of ice .Given that specific latent heat of fusion of ice =336J/g-°c and specific heat capacity of water =4.2J/g-°c
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Explanation:
Mass of ice (m
1
)=40g=
1000
40
kg
Mass of water (m
2
)=200g=
1000
200
kg
Temperature of water 50
o
C. Let final temp. =T
o
C
Heat taken by ice = Heat given by water
m
1
L+m
1
S
1
T
1
=m
2
S
2
T
2
⇒
1000
40
×336×10
3
+
1000
40
×4.2×10
3
×T =
1000
200
×4.2×10
3
×(50−T)
⇒40×336+40×4.2T=200×4.2×(50−T)
⇒336+4.2T=21(50−T)
⇒25.2T=714⇒T=
25.2
714
=28.33
o
C
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