A calorimeter of water equivalent 50 grams contains 350 grams of water at 40 degree Celsius 100 grams of ice is added to the resultant temperature is
Answers
Answer:
Explanation:
total mass of water =400 gm
temperature=40 C
mass of ice =100 gm let final temp be Tm
as we know
Heat released=Heat absorbed
ms(T1-Tm) = mL + ms(Tm-T2)
400*1(40-Tm)=100*80+100*1(Tm-0)
400(40-Tm)=8000+100Tm
4(40-Tm)=80+Tm
160-4Tm=80+Tm
80=5Tm
Tm=16 c
Thank You
Answer:
The resultant temperature for this problem will be 16°C.
Explanation:
Given that:
- Total mass of water = 400 gm
- Temperature = 40°C
- Mass of ice = 100 gm
Let final temp be marked as Tm.
We also know that Heat released = Heat absorbed. The quantity of heat absorbed or emitted by the calorimeter is proportional to the amount of heat produced or consumed by the reaction and has the same sign.
ms(T1 - Tm) = mL + ms(Tm - T2)
400 × 1(40 - Tm) = 100 × 80 + 100 × 1(Tm - 0)
400(40 - Tm) = 8000 + 100Tm
4(40 - Tm) = 80 + Tm
160 - 4Tm = 80 + Tm
80 = 5Tm
So, Tm = 16°C
Thus, when the bonds in the reaction are broken, more energy is absorbed than is produced when new bonds are generated in the products in endothermic reactions.