A cam travelling a bokim per hour over
takes another cour travelling 42 Km/h s
assuming each car 5.0 m long find the
toime taten during the over table and the
total road distance used for the over take
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The velocity of car which is overtaking v1=60×185=50/3m/s
The velocity of car to be overtaken v2=42×185=35/3m/s
The relative velocity between them v12=v1−v2
=350−335=5m/s
The distance traveled by car 1 in overtaking car 2 = 10 m
∴Time taken in overtaking this distance =510=2s
The distance travelled by car 1 in this duration
s=350×2=33.3 m
The total distance used for overtake=s+5=33.3+5=38
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