Math, asked by anandrishav3516, 4 months ago

A camp had provisions for 300 soldiers for 90 days. After 20 days, 50 soldiers left the camp. How
would the food last at the same rate?



Answers

Answered by abhishekkumar728299
10

Answer:

Remaining number of men =(300−50)=250.

Remaining number of days =(90−20)days=70 days

300 men had provisions for 70 days

1 man had provisions for (300×70) days ...[less men, more days]

250 men had provisions for

250

300×70

days =84 days ...[more men, less days]

Hence, the remaining food will last for 84 days.

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