A camp had provisions for 490 soldiers for 65 days. After 15 days, more soldiers arrived and the remaining provisions lasted for 35 days. How many soldiers joined the camp??
Answers
The number of additional soldiers who joined the camp = 210
Provision for 490 soldiers is for 65 days at the camp.
After 15 days -
The provision for 490 soldiers will last for 50 days .
Let the number of soldiers arriving at the camp after 15 days be x.
Total soldiers at the camp = (490+x)
Number of days the provision lasted after new soldiers joined the camp = 35.
For 490 soldiers provision will last for 50 days .
For (490+x) soldiers provision will last for 35 days .
So, 490 × 50 = (490+x) × 35
=> 7350 = 35x
=> x = 210
210 additional soldiers joined the camp.
Answer:
★ Number of soldiers joined the camp was 210 ★
Step-by-step explanation:
Given: Let camp has provision of food
- Provision of food for 490 soldiers is for 65 days
- After 15 days, more soldiers arrived and the remaining provisions lasted for 35 days
To Find:
- Number of soldiers who joined camp
Solution:
† In first case †
Total number of soldiers = 490 and Number of days = 65 days
† In second case † ( After 15 days)
Total number of soldiers= 490 and Number of days = 65–15 = 50 days
★ After 15 days some more soldiers arrived the camp. ★
→ Let number of soldiers joined the camp be x
∴ Number of soldiers = 490 + x and Number of days = 50–15 = 35 days
A/q
Soldiers 490 then Days = 50
Soldiers 490 + x then Days = 35
Here, As the number of soldiers increased then the number of days decreased. Therefore, It is in Inverse Proportion
→ Proportion is (490+x) : 490 : 50 : 30
★ Product of Extremes = Product of Means
(490+x)35 = 490 x 50
17,150 + 35x = 24,500
35x = 24,500–17,150
35x = 7350
x = = 210
Hence, The number of soldiers who joined the camp was 210