Question

A camp has food for 630 men to last for 25 days.how much person should transfer to other camp for food to last 30 days

Answer 1

HEY DEAR . ✌

___________________________



25 days = Food for 630 men

30 days = x           (Inverse variation)

30 * x = 630 * 25

x = 630 * 25/30

   = 21 * 25

   = 525 men.

630 - 525 = 105 men.

Therefore, 105 men must be transferred to another camp so that the food lasts for 30 days.


HOPE , IT HELPS .
FOLLOW ME . ✌

Answer 2

Hey....!! :))
_____________
_____________

Solution:

No. of men for which the provision will last for 25 days = 360

No. of men for which the provision will last for 1 day = 360 x 25

Now, no. of men for which the provision will last for 30 days
= \(\frac{360\times 25}{30}\) = 300

Therefore, 60 men
(360 – 300), must be transferred to another camp so that the provision lasts for 30 days. Ans

___________
___________
I Hope it's help you... :))✌️✌️