Question

a camp has provisions for 60 pupil for 18 days.in how many days the same provisions will finish off if the strength of the camp is increased to 72 pupil?

Answer 1

Answer:

$\red { Provisions \: will \: finish \: in }\green {15\:days }$

Step-by-step explanation:

We know that if the strength of the camp is increased then the same provisions last for number of days decreased.

Therefore, Number of pupil varies inversely to the number of days.

$So\: here , \: \pink {\frac{x_{1}}{x_{2}}=\frac{y_{2}}{y_{1}}}\, Where$

$x_{1} = 60 \: pupil, \: y_{1} = 18 \:days,\\</p><p>x_{2} = 72 \: pupil, \: y_{2} = (?) \:days$

$\implies \frac{60}{72}= \frac{y_{2}}{18}$

$\implies y_{2} = \frac{18\times 60}{72}$

$\implies y_{2} = 15$

Therefore.,

$\red { Provisions \: will \: finish \: in }\green {15\:days }$

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Answer 2

Answer:

Step-by-step explanation:

60 pupils provisions=18 days

1 pupils provisions=18×60=1080

72 pupils provisions=1080÷72=15

Ans=15 days