A camp having 80 inmates has food sufficient for 70 days. How many inmates should leave after 10 days so that the remaining food lasts another 80 days
Answers
Answer:
20 men should leave
Step-by-step explanation:
Given,
A camp having 80 inmates has food sufficient for 70 days
80 men*70 days
How many inmates should leave after 10 days
80 men had provisions for 10 days
80 men* 10 days
Let men to leave is x
(80-x) for the for another 80 days
total=80 men had provision for 10 days+ (80-x)men have to sustain for 80 days
80*70=80*10+(80-x)*80
5600=800+6400-80x
80x=7200-5600
80x=1600
x=20 men
Question :- A camp having 80 inmates, has food sufficient for 70 days. How many inmates should leave after 10 days so that the remaining food lasts another 80 days ?
(A) 25
(B) 24
(C) 20
(D) 16
Solution :-
we know that,
- M1 * D1 = M2 * D2
given that,
- M1 = 80 inmates
- D1 = (70 - 10) = 60 days
- M2 = Let x inmates
- D2 = 80 days.
so,
→ 80 * 60 = x * 80
→ x = 60 inmates .
therefore,
→ Inmates should leave = 80 - 60 = 20 inmates (Ans.)
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