Math, asked by Sweetz4707, 8 months ago

A camp of soldiers has a provision for 60 soldiers, sufficient for 40 days. After 20 days 20 soldiers left the camp. Then find how many more days the provision will last?

Answers

Answered by DarshanJain15
2

Answer:

Please do refer to the above pic attached.

Hope it helps you.

Please do mark it as a Brainliest Answer !

Attachments:
Answered by Yugant1913
10

Answer:

30 days for the remaining soldiers ans.

Step-by-step explanation:

In the camp for 120 soldiers, the ration for 60 days is sufficient.

After 40 days in the camp, ration for 120 soldiers will be sufficient for 60 - 40 = 20 days.

Now, after 40 days 40 soldiers went anywhere.

Then, let for remaining 120 - 40 = 80 soldiers that ration will last for X days.

No. Of soldiers and No. Of days for expenditure of ration are in reciprocal ratio.

Hence, No. Of soldiers : No. Of days : : No. Of days : No. Of days.

120 : 80 :  : x : 20

➔ \:  \:  \:  \frac{120}{80}  =  \frac{x}{2}

➔ \:  \:  \:  \frac{3}{2}  =  \frac{x}{20}

➔2x = 20 \times 3

∴ \:  \:  \:  \: x =  \frac{20 \times 3}{2}  = 30

Hence, the left ration will last for 30 days for the remaining soldiers

Similar questions