A can complete a piece of work 3 times as fast as B. If A
and B together can complete the work in 6 days, how
many days would B alone take to complete the work?
(A) 8
(B) 12
(C) 4
(D) 24
Answers
Answer:
24 days option D
Step-by-step explanation:
A=3B
together means A+B=6 days ... equation 1
when I subtute A value in equation 1
ie 4B=6days
B=24 days
Answer:
B can complete the work in 24 days
Step-by-step explanation:
Given data
A can complete a piece of work 3 times as fast as B
A and B together can complete the work in 6 days
here we need to find how many days B alone can take to complete the work
Let x be the work done by B in 1 day
then the work done by A in 1 day = 3x
the work done by both A and B in 1 day = 3x + x _(1)
number of days require to complete the work A and B together = 6
⇒ the work can be done by both together in 1 day = 1/6 _(2)
⇒ from (1) and (2) x + 3x = 1/6
6 (3x + x) = 1
18x + 6x = 1
24 x = 1
x = 1/24
⇒ the work done by B in 1 day = 1/24
⇒ B can complete the work in 24 days
Option (D) is correct answer