A can complete a piece of work in 12 days which
B and C can complete in 16 and 20 days
respectively. All the three of them started the work,
but A left after 4 days, B left 2 days before the
completion of the work. In how many days was the
work completed?
Answers
Answered by
18
Given :
A = 12 days
B = 16 days
C = 20 days.
A = left 4 days before.
B = left 2 days before.
According to the question :
A = 12 days , Left 4 days before
= 12 - 4
= 8 days.
B = 16 days , Left 2 days before
= 16 - 2
= 14 days.
C = 20 days.
So, total number of days :
A + B + C
= 8 + 14 + 20
= 42 days.
Hence , They finished the work in 42 days.
.
Answered by
79
QUESTION:-
✯ᴀ ᴄᴀɴ ᴄᴏᴍᴘʟᴇᴛᴇ ᴀ ᴘɪᴇᴄᴇ ᴏғ ᴡᴏʀᴋ ɪɴ 12 ᴅᴀʏs ᴡʜɪᴄʜ ʙ ᴀɴᴅ ᴄ ᴄᴀɴ ᴄᴏᴍᴘʟᴇᴛᴇ ɪɴ 16 ᴀɴᴅ 20 ᴅᴀʏs ʀᴇsᴘᴇᴄᴛɪᴠᴇʟʏ. ᴀʟʟ ᴛʜᴇ ᴛʜʀᴇᴇ ᴏғ ᴛʜᴇᴍ sᴛᴀʀᴛᴇᴅ ᴛʜᴇ ᴡᴏʀᴋ, ʙᴜᴛ ᴀ ʟᴇғᴛ ᴀғᴛᴇʀ 4 ᴅᴀʏs, ʙ ʟᴇғᴛ 2 ᴅᴀʏs ʙᴇғᴏʀᴇ ᴛʜᴇ ᴄᴏᴍᴘʟᴇᴛɪᴏɴ ᴏғ ᴛʜᴇ ᴡᴏʀᴋ. ɪɴ ʜᴏᴡ ᴍᴀɴʏ ᴅᴀʏs ᴡᴀs ᴛʜᴇ ᴡᴏʀᴋ ᴄᴏᴍᴘʟᴇᴛᴇᴅ?
ANSWER✔
ACCORDING TO THE QUESTION,
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