Question

A can complete a piece of work in 18 days, B in 20 days and C in 30 days, B and C together start the work and forced to leave after 2 days. The time taken by A alone to complete the remaining work is:

Answer 1

if any doubt free to ask.....

Answer 2

It would take 15 days to complete the remaining work.

Step-by-step explanation:

Consider the provided information.

A can complete a piece of work in 18 days,

Work done by A in one day: $\frac{1}{18}$

B in 20 days and C in 30 days,

Work done by B in one day: $\frac{1}{20}$

Work done by C in one day: $\frac{1}{30}$

B and C together start the work and forced to leave after 2 days.

Work done by B and C in two days:

$2(\frac{1}{20}+\frac{1}{30})=\frac{1}{6}$

That means they completed $\frac{1}{6}$ th part now the remaining part is:

$1-\frac{1}{6}=\frac{5}{6}$

Time taken by A to complete $\frac{5}{6}$ th part:

$\dfrac{\frac{5}{6} }{\frac{1}{18}}=\dfrac{5}{6} \times\dfrac{18}{1}\\ \\=5\times3\\\\=15$

Hence, it would take 15 days to complete the remaining work.

#Learn more

A contractor undertook to do a certain work in 75 days and employed 60 men to do it. after 25 days he found that only one-fourth of the work was done. how many more men must be employed in order that the work may be finished in time?

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