A can complete a piece of work in 24 days and B can complete the work in 36 days. Efficiency of C is twice the efficiency of A and B together. Find the number of days in which C can com- plete the work alone.?
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Answer:
GIVEN :
A can complete the work in 36 days and B can complete the same work in 45 days.
C’s work efficiency is 20% of the work efficiency of A.
CALCULATION :
Let, A’s efficiency = x/day
∴ C’s efficiency = x × 20/100 = 0.2x/day
Let, C can complete the work in a days
According to problem,
⇒ x × 36 = 0.2x × a
⇒ a = 36/0.2
⇒ a = 180
∴ C can complete the work in 180 days
Let, they together can complete the work in = y days
According to problem,
⇒ y (1/36 + 1/45 + 1/180) = 1
⇒ y ((5 + 4 + 1)/180) = 1
⇒ y = 180/10
⇒ y = 18
∴ A, B and C together can complete the work in = 18 days
Step-by-step explanation:
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